A single vision lens has the power of -3.50 -1.25 x 030 with a base curve of +6.00. What would the curves ground on the optical surface be:

Prepare for the Ophthalmic Dispensing Test with flashcards and multiple choice questions, each question offers hints and explanations. Excel in your exam!

To determine the curves ground on the optical surface, we need to consider how the lens power and base curve interact. The given lens has a total power of -3.50 -1.25 x 030, meaning it is a toric lens with a main meridian at 030 degrees having a power of -3.50 diopters and the other meridian at 120 degrees having a power of -4.75 diopters (since the -1.25 cylinder power is being added to the primary meridian).

When we grind the optical surface of a lens, we typically subtract the base curve from the overall power at each respective meridian. The base curve is +6.00, so we will subtract this from the calculated powers at each meridian:

  1. At 030 degrees:
  • The effective power is calculated as follows:

[-3.50 (the sphere power) - 0 (cylinder power not affecting the sphere direction) + 6.00 (base curve) = 2.50].

Therefore, the power at this meridian ends up being +2.50 diopters.

  1. At 120 degrees:
  • The calculation here will follow similarly, acknowledging that the
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